Saturday, October 31, 2020

Quantity of Cement, Sand & Water required for Plastering:



 
Plastering refers to protecting a wall or ceiling by laying a plaster (Cement plaster). Plastering is done to remove surface imperfections caused by brickwork and to keep the surface smooth for painting.

 

There are many different types of plastering materials out of them, cement plaster is extensively used. Some other types of plastering materials include lime plaster, clay plaster, etc.

 

How to select the right plastering material for your house?

In any type of plastering two major factors are considered they are Surface Protection and the cost of material. If the quality of plastering is increased and taken higher, then the cost is affected. If price is considered and Quality of plaster are taken lesser importance then the surface protection is compromised.

 

Plastering material should be cheap and economical.

It should be durable enough to sustain any climatic changes in the entire life span of structure.

Plastering material should have excellent workability which can be applied during any weather conditions.

Let us calculate the quantity raw materials (Cement, Sand & water) required for cement plaster. Though the same process is applicable for any other types of plastering materials.

 

Contents [show]

 

Calculating the quantities of Cement & Sand required for plastering:

General points to be remembered in Plastering work calculation

 

The ratios mentioned in plastering are volumetric ratios of Cement & Sand (Ex. Cement: Sand = 1:5, 1 part of cement and 5 parts of sand in a mortar).

The overall thickness of plastering should be minimum 20mm including two coats.

Cement has a dry density volume of 1440Kg/m3

Each bag of cement weighs = 50 Kgs or 110 lbs.

The Volume of each cement bag = 50Kgs/1440 = 0.0348 m3.

The dry density of sand = 1600Kgs/m3

The plastering is done in two layers (two coats): The first coat of plastering is laid with the thickness of minimum 12mm (usually ranges between 12-15mm) and this coat is called as a Rough coat or Primary coat.

The second coat should be laid with the thickness of 8mm and this is called as a Finish coat or Secondary coat of plastering.

Total Plastering = First coat + Second Coat

 

Different ratios of Cement mortar used for plastering are tabulated below:

Mix Ratio             Areas of usage

1:6 & 1:5              This ratio is usually used for Internal plastering of bricks

1:4          Used for Ceiling and external walls

1:3          As it’s a rich mortar mix and it is used where external walls are prone to severe climatic conditions.

It is also used for repair works.

 

Steps involved in calculation of plastering quantities:

Find the total area of wall to be plastered in Sqm (m2).

Consider the ratio and thickness of plastering

Calculate the Total Volume of Plastering

Find out the Volume of Cement and Sand individually for both the coats

Calculate the total volume of cement & Sand required for plastering

Now coming to the calculation part,

 

We are considering the below values for calculation purpose:

 

Wall width and height is 10m and 10m.

Ratio of First coat of plastering (Cement: Sand = 1:5) with the thickness of 12mm.

the ratio of secondary coat of plastering (Cement: Sand = 1:3) with the thickness of 8mm.

Step 1: Calculate the Area of Plastering

Area = width x height = 10 x 10 = 100m2

 

Step 2: Find the Volume of Plastering

 

Volume of First Coat = Area of Plastering x Thickness of Plastering

 

= 100m2 x 12mm (Convert mm to m)

 

= 100×0.012 = 1.2m3

 

Hence, Volume of First Coat of Plastering = 1.2m3

 

The volume of Second Coat = Area of Plastering x Thickness of Plastering

 

= 100m2 x 8mm (Convert mm to m)

 

= 100×0.008 = 0.8m3

 

Therefore, Volume of Second coat of plastering = 0.8m3

 a

Step 3: Finding the individual quantities of Cement and Sand.

First coat ratio = 1:5 (1 part of Cement and 5 parts of Sand)

 

Total parts = 1+5 = 6

 

Quantity of Cement required for First coat =

 

(Total Volume of first coat plastering x No. of Parts of cement) ÷ Total Parts

 

= 1.2 x 1/6 = 0.2m3

 

Quantity of Sand required for First coat =

 

(Total Volume of first coat plastering x No. of parts of sand) ÷ Total Parts

 

= 0.8 x 5/ 6 = 1.0m3

 

Similarly, for Second coat,

 

Second coat ratio = 1:3 (1 part of cement and 3 parts of sand)

 

Total parts = 1+3 =4

 

Quantity of Cement required for Second coat

 

= (Total Volume of second coat plastering x No. of Parts of cement) ÷ Total Parts

 

= 0.8 x 1/4 = 0.2m3

 

Quantity of Sand required for Second coat

 

= (Total Volume of second coat plastering x No. of parts of sand) ÷ Total Parts

 

= 0.8 x 3/4 = 0.6m3

 

Step 4: Finding the quantity of water required for plastering:

Amount of water to be added in mix depends upon the moisture content present in cement, sand & atmosphere.

 

Quantity of water = 20% of total dry material (Cement + Sand)

= 20% of (574+2560) = 0.2 x 3134 = 627 liters.

 

Final Result:

As mentioned above volume of 1 bag of cement (50kgs) = 0.0348m3

For 0.4m3 = 0.4 x 50 / 0.0348 = 574Kgs = 11.4bags

 

Similarly, for Sand 1m3 = 1600Kgs.

1.6 m3 = 1.6 x 1600 = 2560Kgs = 2.5tonnes

Quantity of Water required = 627litres.

 

How many bags of cement are required for 1 square meter of plastering?

If the above-mentioned values are considered for this then (Rough estimate)

 

From above, 100m2= 574 Kgs of cement

1m2 = 574/100 = 5.7Kgs

 

Summary:

 

Quantity of Cement, Sand & Water required for Plastering. For 100m2 of Wall, if first & second coat of cement mortar ratio 1:5 & 1:3 laid then

The Quantity of cement required = 574Kgs

Calculated Quantity of Sand (Fine aggregate) required = 2560Kgs

Quantity of Water required = 627 litters.

Wednesday, August 19, 2020

THE STANDARD FOR PROJECT MANAGEMENT






This guide is based on The Standard for Project Management [1]. A standard is a document established by an authority, custom, or general consent as a model for example. As an American National Standards Institute (ANSI) standard, The Standard for Project Management was developed using a process based on the concepts of consensus, openness, due process, and balance. The Standard for Project Management is a foundational reference for PMI’s project management professional development programs and the practice of project management. Because project management needs to be tailored to fit the needs of the project, the standard and the guide are both based on descriptive practices, rather than prescriptive practices. Therefore, the standard identifies the processes that are considered good practices on most projects, most of the time. The standard also identifies the inputs and outputs that are usually associated with those processes. The standard does not require that any particular process or practice be performed. The Standard for Project Management is included as Part II of A Guide to the Project Management Body of Knowledge (PMBOK® Guide).
The PMBOK® Guide provides more detail about key concepts, emerging trends, considerations for tailoring the project management processes, and information on how tools and techniques are applied to projects. Project managers may use one or more methodologies to implement the project management processes outlined in the standard. 

Friday, June 26, 2020

Assignment #3 how to Download the PMP handbook?




Assignment #3 Download the PMP handbook PMI, PMP exam preparation Course Tutorials, Project Management Professionals

Thursday, May 21, 2020

Chlorine Removal from Your Drinking Water



Watch this video to know how much chlorine your tap water may have. What happens to chlorine in water when you wash fruits and vegetables in such water? How much chlorine you daily intake and why Kangen Water Machine is required to remove this chlorine from your water.

Common Drinks and their pH Level



Watch the video to understand how Acidic or Alkaline is water and beverages you drink every day. How Healthy or Unhealthy it is for you.

What is ORP (Oxidation Reduction Potential)



Antioxidants in Kangen Water Antioxidants are measured in terms of Oxidation Reduction Potential (ORP). While +ve ORP implies Oxidising, Aging and bad for you, the -ve ORP indicates powerful Antioxidants. Watch the Video and know the ORP Levels of your Favorite Drinks.

Monday, May 11, 2020

How to calculate Cutting length of Stirrups in Beam and column


How to calculate Cutting length of Stirrups in Beam and column

To cater to the stresses and loads in RCC, Bars are bent to different shapes in the bar bending schedule.
Different shapes of bars have different cutting lengths. In this post, we are going to explain to you “How to calculate or find the cutting length of Stirrups for different shapes”.
Remember,
The transverse reinforcement provided in Column is called Ties and the transverse reinforcement provided in Beam is called Stirrups. But on-site, we usually call both transverse reinforcements as Stirrups.
The prime reason for providing the stirrups in the beam is for shear requirements and to keep the longitudinal bars in position.
Deducting the concrete cover is most important in Bar bending, if you don't know how to deduct the concrete cover then refer this post

Steps involved in finding the cutting length of stirrups:-

  1. Look at the size of column or beam from drawings
  2. Adopt Dia of the bar (generally 8mm Dia is used for stirrups)
  3. Deduct the concrete cover or clear cover
  4. Find the total outer length of stirrup after deducting concrete cover.
  5. Add the length of the hook to the length of the stirrup
  6. Deduct the length of bends
  7. Use below formula to find the total cutting length of stirrups

Formula: Cutting Length of Stirrups = Perimeter of Shape + Total hook length – Total Bend Length

Important Basic formulas:
Perimeter of Rectangle = 2 ( length + breadth)
Perimeter of Square = 4 x side length
Perimeter of circle or Circumference of Circle = 2πr = πd (r= radius, d= Diameter of Circle)

Typical Diagram of Stirrup:-

Refer the below image of the typical diagram of stirrup for clear understanding about x & y length, bends, hooks, and concrete cover.
typical stirrup diagram
In the above image, there are 5 bends at 4 corners, 2 hooks, and concrete cover around the stirrup.
x = length of the stirrup in the x-direction after deducting concrete cover &
y = length of the stirrup in the y-direction after deducting concrete cover.

Important standards used in Bends & Hooks:

The below standards are most important in calculating the hook length and bend lengths at corners while finding the cutting length of stirrups.
  • 1 Hook length = 9d or 75mm
  • 45° Bend length = 1d
  • 90° Bend length = 2d
  • 135° Bend length = 3d
Remember, d = Diameter of Bar

Cutting length for Rectangular Stirrups:-

The rectangular column or rectangular beam is the most commonly used shape of the column in any construction. In this shape of beam or column, a rectangular stirrup is usually adopted.
  1. Considering the below Rectangular column size 230mm x 450mm for calculation purpose
    rectangular column details
  2. Adopting Dia of Bar used for stirrups is 8mm
  3. Deducting the concrete cover 20mm from all sides
    x = 230 – 20-20 = 190mm
    y = 450-20-20 = 410mm
    cutting length of rectangular stirrup
  4. Total Length of the hooks:
    From fig, There are two hooks which mean 9d+9d = 18d
  5. Total Length of Bends:
    From above fig, There are 3 bends which are bent at an angle of 900 and two bends are bent at an angle of 1350
    Total bend length = 3 x 900 Bend length + 2 x 1350 Bend length = 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm
Total Cutting length of Rectangular Stirrup = Perimeter of Rectangle + Total Hook length – Total Bend Length
= 2 (x+y) +18d – 12d = 2(190 + 410) + 18 x 8 – 12 x 8 = 1248mm = 1.248m

Cutting length for Square Stirrups:-

  1. Considered the column size as 450mm x 450mm
    square stirrup details
  2. Adopting Dia of Bar used for stirrups is 8mm
  3. Deducting the concrete cover 25mm from all sides (in the square all sides are equal)
    x = 450- 20-20 = 410mm
    y = 450-20-20 = 410mm, Hence x = y (in square all sides are equal)
    Square stirrup deductions
  4. Total Length of the hook:
    There are two hooks which mean 9d+9d = 18d
  5. The total length of Bends:
    There are 3 bends that are bent at an angle of 900 and one is bent at an angle of 1350.
    Total bend length = 3 x 900 Bend length + 2 x 1350 Bend length = 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm
    square stirrup details
Total Cutting length of Square Stirrup = Perimeter of Square + Total Hook length – Total Bend Length
= 4 x 410 +18d – 12d = 1648mm = 1.64m

Cutting Length for Circular Stirrup:

  1. Considered the column dia as D = 1000mm
  2. Adopting Dia of Bar used for stirrups is d =8mm
    Circular Stirrups details
  3. Deducting the concrete cover from diameter of column
    D = 1000-25-25 = 950mm
    circular stirrup with hooks and bends
  4. Circumference length of Ring = πD = 950 x 3.14 = 2983mm
  5. Total Length of the hook:
    There are two hooks which means 9d+9d= 18d
  6. Total Length of Bends:
    There are 2 bends which are bent at an angle of 1350
    Total bend length = 2 x 1350 Bend length = 2 x 3d = 6d= 6 x 8 = 48mm
Total Cutting length of Circular Stirrup or Ring = Circumference of Circle + Total Hook length – Total Bend Length= 2983 +18d – 6d =3079mm =3.07m

Cutting Length for Triangular Stirrups:

  1. Considered the Column size 400mm x 450mm
    traingular stirrup details
  2. Adopting Dia of Bar used for stirrups is d = 8mm
  3. Deducting the concrete cover 25mm from all sides
    x = 400-20-20 = 360mm
    y = 450-20-20 = 410mm
    From Pythagorean theorem,
    Hypotenuse2=(Opposite)2 + (Adjacent)2 
    finding hypotnuse in triangular stirrup
    look at 2nd triangle in above image
    H2=(x/2)2 + y2
    H2=1802 + 4102 => =  √(447)2  = 447mm
    The total length of stirrup till now = 2 x H + 360 = 2 x 447 + 360 = 1254mm
  4. Total Length of the hooks: 
    There are two hooks which means 9d+9d= 18d
    Triangular stirrup Hooks and Bend Lengths
  5. Total length of Bends:
    There are 4 bends which are bent at an angle of 1350
    Total bend length =4 x 1350 Bend length=  4 x 3d = 12d= 12 x 8 = 96mm
Total Cutting length of Triangular Stirrup = Perimeter of Triangle + Total Hook length – Total Bend Length
= 1254+18d – 12d = 1302mm = 1.3m

Cutting Length for Diamond Stirrups:

  1. Considered the Column size 400mm x 400mm
    diamond stirrup details
  2. Adopting Dia of Bar used for stirrups is d = 8mm
  3. Deducting the concrete cover 25mm from all sides
    x = 400-20-20 = 360mm
    y = 400-20-20 =360mm
    diamond stirrups hook length and bend length
    From Pythagorean theorem,
    Hypotenuse2=(Opposite)2 + (Adjacent)2 
    H2=(x/2)2 +( y/2)2
    H2=1802 + 1802 => =  √(254)2  = 254mm
  4. The total length of stirrup = 4 x H  =4 x 254 = 1016mm
  5. Total Length of the hook:
    There are two hooks which means 9d+9d= 18d
  6. Total length of Bends:
    There are 3 bends which are bent at an angle of 90 + 2 bends which are bent at an angle of 1350
    Total bend length = 3 x 900 Bend length + 2 x 1350 Bend length= 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm
Total Cutting length of Diamond  Stirrup = Perimeter of Diamond shape + Total Hook length – Total Bend Length= 1016+144-96 = 1064mm = 1.064mm
I hope now you can easily find the cutting length for different types of stirrups.